Question:
Wurtz's reaction involves'the reduction of alkyl halide with:
Wurtz's reaction involves'the reduction of alkyl halide with:
Updated On: Jun 20, 2022
- $ ~Zn/HCl $
- $ HI $
- $ Zn/Cu $ couple
- Na in ether
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The Correct Option is D
Solution and Explanation
Write Wurtz reaction $ \underset{\text{alkyl}\,\text{halide}}{\mathop{2R-X}}\,+\underset{\text{Sodium}}{\mathop{2Na}}\,\xrightarrow{\text{ehter}}\underset{\text{alkane}}{\mathop{R-R}}\,+2NaX $ $ \therefore $ Na in ether'is correct answer.
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Concepts Used:
Preparation of Haloalkanes
- Preparation by Alcohols: By using alcohol, we can very easily prepare Haloalkane as when R-OH is reacted with a suitable reagent it will form R-X. The following reagents will help in the formation of the reactions:
- Halogen Acids (HX)
- Thionyl chloride (SOCl2)
- Phosphorous halides (PX5 or PX3)
- Preparation by Free Radical Halogenation: The formation of alkyl bromides and alkyl chloride is very much possible with the help of free radical halogenation, but as these radicals are highly reactive and non-specific in nature, they can result in the formation of a mixture of products. Though, it's not a preferred method for the preparation of haloalkanes. For example, free radical chlorination can result in the formation of a number of haloalkanes, which in turn makes it difficult to set apart a single product.
- Preparation by Alkenes: An electrophilic addition reaction can be used to transform an alkene into a haloalkane as alkene will react with HX to form R-X.
Read More: Haloalkanes and Haloarenes