Question:
The conversion of ethyl bromide to ethyl iodide using sodium iodide and dry acetone, this reaction is known as
The conversion of ethyl bromide to ethyl iodide using sodium iodide and dry acetone, this reaction is known as
Updated On: Apr 7, 2024
- Swarts reaction
- Finkelstein reaction
- Sandmeyer reaction
- Stephen reaction
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The Correct Option is B
Solution and Explanation
The conversion of ethyl bromide to ethyl iodide using sodium iodide and dry acetone, this reaction is known as Finkelstein reaction.
$C _{2} H _{5}- Br + NaI \rightarrow C _{2} H _{5} I + NaBr$
In dry acetone, sodium bromide gets precipitated.
$C _{2} H _{5}- Br + NaI \rightarrow C _{2} H _{5} I + NaBr$
In dry acetone, sodium bromide gets precipitated.
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Concepts Used:
Preparation of Haloalkanes
- Preparation by Alcohols: By using alcohol, we can very easily prepare Haloalkane as when R-OH is reacted with a suitable reagent it will form R-X. The following reagents will help in the formation of the reactions:
- Halogen Acids (HX)
- Thionyl chloride (SOCl2)
- Phosphorous halides (PX5 or PX3)
- Preparation by Free Radical Halogenation: The formation of alkyl bromides and alkyl chloride is very much possible with the help of free radical halogenation, but as these radicals are highly reactive and non-specific in nature, they can result in the formation of a mixture of products. Though, it's not a preferred method for the preparation of haloalkanes. For example, free radical chlorination can result in the formation of a number of haloalkanes, which in turn makes it difficult to set apart a single product.
- Preparation by Alkenes: An electrophilic addition reaction can be used to transform an alkene into a haloalkane as alkene will react with HX to form R-X.
Read More: Haloalkanes and Haloarenes