Step 1: Understanding the Concept:
Specific resistance, also known as resistivity, is an intrinsic property of a material that quantifies how strongly it resists the flow of electric current. It is denoted by the Greek letter \(\rho\) (rho).
Step 2: Key Formula or Approach:
The resistance \(R\) of a uniform conductor is related to its resistivity (\(\rho\)), length (\(L\)), and cross-sectional area (\(A\)) by the formula:
\[ R = \rho \frac{L}{A} \]
We can rearrange this formula to solve for resistivity \(\rho\):
\[ \rho = \frac{R \cdot A}{L} \]
Step 3: Detailed Explanation:
To find the unit of resistivity, we can substitute the SI units for the quantities on the right side of the rearranged formula:
\begin{itemize}
\item The unit of resistance (\(R\)) is the ohm (\(\Omega\)).
\item The unit of area (\(A\)) is the square meter (\(m^2\)).
\item The unit of length (\(L\)) is the meter (\(m\)).
\end{itemize}
Substituting these units into the equation for \(\rho\):
\[ \text{Unit of } \rho = \frac{\text{Unit of } R \times \text{Unit of } A}{\text{Unit of } L} = \frac{\Omega \cdot m^2}{m} \]
Simplifying the expression, we get:
\[ \text{Unit of } \rho = \Omega \cdot m \]
Step 4: Final Answer:
The SI unit of specific resistance (resistivity) is the ohm-meter (\(\Omega \cdot m\)).

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \[ (R_1=R_2=R_3=R_4). \] When \(R_3\) resistance is heated, its resistance value increases by \(10%\). The potential difference \((V_a-V_b)\) after \(R_3\) is heated is _______ V. 