Question:
Write the structure of the product for the reaction:
\[
\text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{CH}_2\text{NH}_2 \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2
\]
Write the structure of the product for the reaction:
\[ \text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{CH}_2\text{NH}_2 \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2 \]
\[ \text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{CH}_2\text{NH}_2 \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2 \]
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Reduction of carboxylic acids with amines in acidic conditions results in the formation of secondary amines, such as phenylethylamine in this case.
Updated On: Sep 3, 2025
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Solution and Explanation
This reaction is a reduction of benzoic acid (C\(_6\)H\(_5\)COOH) with an amine (ethylamine) in the presence of an acid (\(H^+\)) to form phenylethylamine.
\[
\text{C}_6\text{H}_5\text{COOH} + \text{CH}_3\text{CH}_2\text{NH}_2 \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2
\]
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