Question

Write the structure of the product for the reaction:
\[ \text{C}_6\text{H}_6 + \text{C}_2\text{H}_5\text{Cl} \xrightarrow{\text{Anhydrous AlCl}_3} \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \]

Hint:

In Friedel-Crafts alkylation reactions, the alkyl group is introduced into the aromatic ring using a strong Lewis acid, such as anhydrous AlCl\(_3\).

Answer 1

The reaction involves the Friedel-Crafts alkylation of benzene using ethyl chloride in the presence of anhydrous AlCl\(_3\). This results in the formation of ethylbenzene. \[ \text{C}_6\text{H}_6 + \text{C}_2\text{H}_5\text{Cl} \xrightarrow{\text{Anhydrous AlCl}_3} \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \]