Question:

Write the structure of the product for the reaction:
\[ \text{C}_6\text{H}_6 + \text{C}_2\text{H}_5\text{Cl} \xrightarrow{\text{Anhydrous AlCl}_3} \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \]

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In Friedel-Crafts alkylation reactions, the alkyl group is introduced into the aromatic ring using a strong Lewis acid, such as anhydrous AlCl\(_3\).
Updated On: Sep 3, 2025
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Solution and Explanation


The reaction involves the Friedel-Crafts alkylation of benzene using ethyl chloride in the presence of anhydrous AlCl\(_3\). This results in the formation of ethylbenzene. \[ \text{C}_6\text{H}_6 + \text{C}_2\text{H}_5\text{Cl} \xrightarrow{\text{Anhydrous AlCl}_3} \text{C}_6\text{H}_5\text{C}_2\text{H}_5 \]
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