Question:
Identify (A)
Identify (A)
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$\text{Zn}$ dust mediates reductive elimination of vicinal dihalides to form alkenes. $\text{HBr}$ addition to a simple alkene yields the alkyl halide via carbocation formation (Markovnikov rule).
Updated On: Jan 25, 2026
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The Correct Option is C
Solution and Explanation
Step 1: The given compound is a vicinal dibromide of cyclopentane.
Step 2: Vicinal dihalides on heating with zinc undergo dehalogenation:
\[
R-CHBr-CHBr-R \xrightarrow{Zn/\Delta} R-CH=CH-R
\]
Step 3: Hence, cyclopentene is formed as intermediate.
Step 4: Cyclopentene reacts with $HBr$ via electrophilic addition.
Step 5: Since cyclopentene is symmetrical, only one major brominated product is formed.
Step 6: The structure corresponds to the one shown in option (3).
Hence, correct answer is (3).
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