Question

Write the products in the following reactions:

Hint:

- The reaction of aldehydes and methyl ketones with NaOH and I\(_2\) leads to the formation of iodoform (CHI\(_3\)). - The reaction with dimethylcadmium results in the formation of a ketone and the release of CdCl\(_2\).

Answer 1

(A) The reaction of acetophenone (C\(_6\)H\(_5\)COCH\(_3\)) with NaOH and I\(_2\) forms a yellow precipitate of iodoform (CHI\(_3\)) as follows: \[ \text{C}_6\text{H}_5\text{COCH}_3 + \text{NaOH/I}_2 \rightarrow \text{C}_6\text{H}_5\text{COONa} + \text{CHI}_3 \]

(B) The reaction of benzoyl chloride (C\(_6\)H\(_5\)COCl) with dimethylcadmium ((CH\(_3\))\(_2\)Cd) results in the formation of a ketone (C\(_6\)H\(_5\)COCH\(_3\)) and cadmium chloride (CdCl\(_2\)) as follows: \[ \text{C}_6\text{H}_5\text{COCl} + (CH_3)_2\text{Cd} \rightarrow \text{C}_6\text{H}_5\text{COCH}_3 + \text{CdCl}_2 \]