Natural numbers from \(102\) to \(113\): \(102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113\)
Prime numbers from \(102\) to \(113\): \(103, 107, 109, 113\)
Hence fraction of prime numbers = \(\frac{4 }{12} =\frac{1}{3}\)
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow