The mechanism for the dehydration of ethanol (CH3CH2OH) to ethene (CH2=CH2) under acidic conditions involves the following steps:
Step 1: Formation of protonated alcohol (Fast step)
Ethanol (CH3CH2OH) reacts with the proton (H+) to form the protonated alcohol (ethyl oxonium ion).
CH3CH2OH + H+ → CH3CH2OH+
Step 2: Formation of carbocation (Slow step)
The protonated alcohol undergoes the loss of water to form a carbocation, which is the rate-determining step.
CH3CH2OH+ → CH3C+ + H2O
Step 3: Formation of ethene by elimination of a proton (Fast step)
The carbocation formed in Step 2 loses a proton to form ethene.
Overall reaction:
CH3C+CH2 → C2H4 (Ethene) + H+
Balance Sheet of Chandan, Deepak and Elvish as at 31st March, 2024
Liabilities | Amount (₹) | Assets | Amount (₹) |
---|---|---|---|
Capitals: | Fixed Assets | 27,00,000 | |
Chandan | 7,00,000 | Stock | 3,00,000 |
Deepak | 5,00,000 | Debtors | 2,00,000 |
Elvish | 3,00,000 | Cash | 1,00,000 |
General Reserve | 4,50,000 | ||
Creditors | 13,50,000 | ||
Total | 33,00,000 | Total | 33,00,000 |
A coil of 60 turns and area \( 1.5 \times 10^{-3} \, \text{m}^2 \) carrying a current of 2 A lies in a vertical plane. It experiences a torque of 0.12 Nm when placed in a uniform horizontal magnetic field. The torque acting on the coil changes to 0.05 Nm after the coil is rotated about its diameter by 90°. Find the magnitude of the magnetic field.