Question:

In the reaction R–OH + HCl $\xrightarrow{\text{ZnCl}_2}$ RCl + H$_2$O, what is the correct order of reactivity of alcohols?

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More substituted alcohols form more stable carbocations, increasing reactivity.
  • 1$^\circ$ $<$ 2$^\circ$ $<$ 3$^\circ$
  • 2$^\circ$ $<$ 1$^\circ$ $<$ 3$^\circ$
  • 3$^\circ$ $>$ 1$^\circ$ $<$ 2$^\circ$
  • 1$^\circ$ $>$ 2$^\circ$ $>$ 3$^\circ$
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The Correct Option is A

Solution and Explanation

Lucas reagent (HCl + ZnCl$_2$) reacts fastest with tertiary alcohols due to the formation of stable carbocations, so the order is 1$^\circ$ $<$ 2$^\circ$ $<$ 3$^\circ$.

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