Question

Write the end product of the following reaction:

• A.
• B.
• C.
• D.

Hint:

In nucleophilic aromatic substitution reactions, groups like methoxy (\( \text{MeO} \)) replace halogens (like chlorine) on the benzene ring, especially at the para- or ortho- positions.

Answer 1

The Correct Option is B

Step 1: Understand the reaction type.
This is a nucleophilic substitution reaction, where the methoxy group (\( \text{MeO} \)) from the sodium methoxide (\( \text{NaOCH}_3 \)) replaces one of the chlorine atoms on the benzene ring.
Step 2: Methoxy group as a nucleophile.
The methoxy group (\( \text{MeO} \)) is an electron-donating group and acts as a nucleophile. Under the reaction conditions (using \( \text{NaOCH}_3/\text{MeOH} \)), the methoxy group replaces the chlorine atom in a nucleophilic substitution at the position that is ortho or para to the nitro group.
Step 3: Substitution outcome.
Since the methoxy group is nucleophilic and the chlorine is a leaving group, the substitution occurs at the available site (para to the nitro group), yielding the final product as \( \text{NO}_2 \text{C}_6\text{H}_3(\text{MeO}) \).