Answer:
ΔG < 0 (Negative Gibbs free energy change)
Explanation:
The change in Gibbs free energy is given by: \[ \Delta G = \Delta H - T\Delta S \]
- A process is **spontaneous** when ΔG is **negative**. - It is **non-spontaneous** when ΔG is **positive**. - It is at **equilibrium** when ΔG = 0.
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is _____ $ \times 10^{-1} $ J. (Take $ \pi = 3.14 $) 
Match List - I with List - II.

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