Question:
Write the chemical equations for two chemical properties of ethanol.
Write the chemical equations for two chemical properties of ethanol.
Show Hint
Ethanol reacts with active metals like sodium to produce hydrogen gas and undergoes oxidation to form acetic acid.
Updated On: Nov 5, 2025
Hide Solution
Verified By Collegedunia
Solution and Explanation
Step 1: Reaction with Sodium.
When ethanol reacts with sodium metal, hydrogen gas is evolved and sodium ethoxide is formed. \[ 2\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \rightarrow 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \uparrow \] Observation: Bubbles of hydrogen gas are seen during the reaction.
Step 2: Oxidation of Ethanol.
On oxidation with acidified potassium dichromate (K2Cr2O7), ethanol is oxidized to acetic acid. \[ \text{C}_2\text{H}_5\text{OH} + [O] \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}_2\text{SO}_4} \text{CH}_3\text{COOH} + \text{H}_2\text{O} \] Step 3: Conclusion.
Ethanol exhibits the properties of alcohols by reacting with metals to form alkoxides and by oxidation to form carboxylic acids.
When ethanol reacts with sodium metal, hydrogen gas is evolved and sodium ethoxide is formed. \[ 2\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \rightarrow 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \uparrow \] Observation: Bubbles of hydrogen gas are seen during the reaction.
Step 2: Oxidation of Ethanol.
On oxidation with acidified potassium dichromate (K2Cr2O7), ethanol is oxidized to acetic acid. \[ \text{C}_2\text{H}_5\text{OH} + [O] \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}_2\text{SO}_4} \text{CH}_3\text{COOH} + \text{H}_2\text{O} \] Step 3: Conclusion.
Ethanol exhibits the properties of alcohols by reacting with metals to form alkoxides and by oxidation to form carboxylic acids.
Was this answer helpful?
0
0
Top Questions on Inorganic chemistry
- Given below are some of the statements about Mn and \( Mn_2O_7 \). Identify the correct statements.
A. Mn forms the oxide \( Mn_2O_7 \), in which Mn is in its highest oxidation state.
B. Oxygen stabilizes the Mn in higher oxidation states by forming multiple bonds with Mn.
C. \( Mn_2O_7 \) is an ionic oxide.
D. The structure of \( Mn_2O_7 \) consists of one bridged oxygen.
Choose the correct answer from the options given below :- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- On heating a mixture of common salt and \( K_2Cr_2O_7 \) in equal amount along with concentrated \( H_2SO_4 \) in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are :
- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- Given below are two statements :
Statement I : The correct order in terms of atomic/ionic radii is \( Al>Mg>Mg^{2+}>Al^{3+} \).
Statement II : The correct order in terms of the magnitude of electron gain enthalpy is \( Cl>Br>S>O \).
In the light of the above statements, choose the correct answer from the options given below :- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- Consider the following statements:
[(A)] \(\mathrm{KMnO_4}\) is diamagnetic while \(\mathrm{K_2MnO_4}\) is paramagnetic.
[(B)] Manganate ion contains \(\mathrm{Mn^{6+}}\) while permanganate ion contains \(\mathrm{Mn^{7+}}\).
[(C)] \(\mathrm{Mn^{2+}}\) ion on reaction with \(\mathrm{S_2O_8^{2-}}\) ions gives manganate ion.
[(D)] Both \(\mathrm{MnO_4^-}\) and \(\mathrm{MnO_4^{2-}}\) are tetrahedral.
Correct statements are:- JEE Main - 2026
- Chemistry
- Inorganic chemistry
- Statement-I : \(\mathrm{KMnO_4}\) is a good reducing agent.
Statement-II : \(\mathrm{KMnO_4}\) reduces nitrite, oxalate and iodide ions.- JEE Main - 2026
- Chemistry
- Inorganic chemistry
View More Questions
Questions Asked in UP Board X exam
- Colour origin from
- UP Board X - 2025
- Light and Colour
- How many national political parties are there in India?
- UP Board X - 2025
- Parties and the Party Systems in India
- Prime factorisation of 156 will be:
- UP Board X - 2025
- Number System
- (i) Food chain
(ii) Growth hormone in human.- UP Board X - 2025
- Food Chains and Energy Flow
- A lemon placed in a beaker full of water appears larger than its real size, when viewed sideways. The light phenomenon responsible is -
- UP Board X - 2025
- Refraction of Light
View More Questions