Question:
Write the chemical equation when:
(a) Butan-2-one is treated with Zn(Hg) and conc. HCl.
(b) Two molecules of benzaldehyde are treated with conc. NaOH.
Write the chemical equation when:
(a) Butan-2-one is treated with Zn(Hg) and conc. HCl.
(b) Two molecules of benzaldehyde are treated with conc. NaOH.
(a) Butan-2-one is treated with Zn(Hg) and conc. HCl.
(b) Two molecules of benzaldehyde are treated with conc. NaOH.
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The Clemmensen reduction removes the carbonyl group, and benzoin condensation couples two benzaldehyde molecules to form benzoin.
Updated On: Feb 26, 2025
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Solution and Explanation
(a) The reaction of butan-2-one with Zn(Hg) and conc. HCl is the Clemmensen reduction, which reduces the ketone to an alkane.
\[
\text{CH}_3\text{COCH}_2\text{CH}_3 \xrightarrow{\text{Zn(Hg), HCl}} \text{CH}_3\text{CH}_2\text{CH}_3
\]
(b) The reaction of benzaldehyde with conc. NaOH is the benzoin condensation, which forms benzoin.
\[
2 \text{C}_6\text{H}_5\text{CHO} \xrightarrow{\text{conc. NaOH}} \text{C}_6\text{H}_5\text{CHOH}\text{C}_6\text{H}_5
\]
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