Question

Write Lewis dot symbols for atoms of the following elements: Mg, Na, B, O, N, Br.

Answer 1

\(\text{Mg}\) : There are two valence electrons in \(\text{Mg}\) atom.
⇒ Hence, the Lewis dot symbol for \(\text{Mg}\) is:

\(\text{Na}\) : There is only one valence electron in an atom of sodium.
⇒ Hence, the Lewis dot structure is:

\(\text{B}\): There are 3 valence electrons in Boron atom.
⇒ Hence, the Lewis dot structure is:

\(\text{O}\) There are six valence electrons in an atom of oxygen.
⇒ Hence, the Lewis dot structure is:

\(\text{N}\): There are five valence electrons in an atom of nitrogen.
⇒ Hence, the Lewis dot structure is:

\(\text{Br}\): There are seven valence electrons in bromine.
⇒ Hence, the Lewis dot structure is: