Electronic configuration of carbon atom:
\(_6C\): \(1s^ 2 2s^ 2 2p^ 2 \)
In the excited state, the orbital picture of carbon can be represented as:
Hence, carbon atom undergoes sp \(3\) hybridization in \(CH_4\) molecule and takes a tetrahedral shape.
For a square planar shape, the hybridization of the central atom has to be \(dsp ^2\) . However, an atom of carbon does not have \(d-orbit\) alsto undergo \(dsp ^2\) hybridization. Hence, the structure of \(CH_4\) cannot be square planar.
Moreover, with a bond angle of \(90\degree\) in square planar, the stability of \(CH_4\) will be very less because of the repulsion existing between the bond pairs.
Hence, VSEPR theory also supports a tetrahedral structure for \(CH_4\).
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.