Let the work done by A, B, and C in 1 day be A, B, and C respectively.
From the given conditions:
\[ A + B = \frac{1}{10}, \quad B + C = \frac{1}{12}, \quad C + A = \frac{1}{15}. \]
\[ (A + B) + (B + C) + (C + A) = \frac{1}{10} + \frac{1}{12} + \frac{1}{15}. \]
Rearranging:
\[ 2(A + B + C) = \frac{6}{60} + \frac{5}{60} + \frac{4}{60} = \frac{15}{60} = \frac{1}{4}. \]
Dividing by 2:
\[ A + B + C = \frac{1}{8}. \]
The total time required to complete the work when all three work together is:
\[ \text{Time} = \frac{1}{A + B + C} = \frac{1}{\frac{1}{8}} = 8 \text{ days}. \]
The time required to complete the work is 8 days.