Given:
Let the actual time taken by Anu, Tanu, and Manu be \(5x, 8x, 10x\) respectively.
Take total work as LCM of the times: \(\text{LCM}(5x, 8x, 10x) = 40x\)
Combined rate = \(8 + 5 + 4 = 17\) units/hour
They work 8 hours per day for 4 days: \(8 \times 4 = 32\) hours
Total work = \(17 \times 32 = 544\) units
But total work = \(40x\), so:
They work together for 6 days, 6 hours 40 minutes per day.
Convert 6 hours 40 minutes to hours: \(6 + \frac{40}{60} = \frac{20}{3}\) hours/day
Total hours worked = \(6 \times \frac{20}{3} = 40\) hours
Combined rate = \(8 + 5 = 13\) units/hour
Work done = \(13 \times 40 = 520\) units
Total work = \(40x = 544\)
Remaining work = \(544 - 520 = 24\) units
Manu’s rate = 4 units/hour
Time = \(\frac{24}{4} = 6\) hours
Given that, the times taken by Anu, Tanu, and Manu to complete any job are in the ratio \(5:8:10\)
Therefore, the efficiency will be in the ratio,
\(= \frac{40}{5} : \frac{40}{8} : \frac{40}{10}\)
\(= 8 : 5 : 4\)
Hence, Anu does \(8\) units per hour, Tanu does \(5\) units per hour, and Manu does \(4\) units per hour.
Total work \(= 4 \times 8 \times (8 + 5 + 4)\)
\(= 4 \times 8 \times 17 = 544\)
Work done by Anu and Tanu in \(6 \times 6.67\) hours:
\(= 6 \times 6.67 \times (8 + 5)\)
\(= 6 \times 6.67 \times 13 = 520\)
Remaining work:
\(= 544 - 520 = 24\)
Time taken by Manu to complete remaining work:
\(= \frac{24}{4} = 6\) hours
When $10^{100}$ is divided by 7, the remainder is ?