To determine the velocity with which an observer should approach a stationary sound source so that the apparent frequency becomes double the actual frequency, we can use the Doppler effect formula for sound. The formula for the apparent frequency (\(f'\)) perceived by an observer approaching a stationary sound source is given by:
\[f' = \left(\frac{v + v_o}{v}\right)f\]
Where:
Since we want the apparent frequency to be double the actual frequency, we set up the equation:
\[2f = \left(\frac{v + v_o}{v}\right)f\]
Dividing both sides by \(f\), we get:
\[2 = \frac{v + v_o}{v}\]
Multiplying both sides by \(v\) results in:
\[2v = v + v_o\]
Solving for vo, we subtract \(v\) from both sides:
\[v_o = 2v - v\]
\[v_o = v\]
Therefore, the observer should approach the stationary sound source with a velocity equal to the speed of sound (\(v\)) to perceive the frequency as double the actual frequency.
The correct answer is: \(\mathbf{v}\)
Two loudspeakers (\(L_1\) and \(L_2\)) are placed with a separation of \(10 \, \text{m}\), as shown in the figure. Both speakers are fed with an audio input signal of the same frequency with constant volume. A voice recorder, initially at point \(A\), at equidistance to both loudspeakers, is moved by \(25 \, \text{m}\) along the line \(AB\) while monitoring the audio signal. The measured signal was found to undergo \(10\) cycles of minima and maxima during the movement. The frequency of the input signal is _____________ Hz.
(Speed of sound in air is \(324 \, \text{m/s}\) and \( \sqrt{5} = 2.23 \)) 
200 ml of an aqueous solution contains 3.6 g of Glucose and 1.2 g of Urea maintained at a temperature equal to 27$^{\circ}$C. What is the Osmotic pressure of the solution in atmosphere units?
Given Data R = 0.082 L atm K$^{-1}$ mol$^{-1}$
Molecular Formula: Glucose = C$_6$H$_{12}$O$_6$, Urea = NH$_2$CONH$_2$