Question

With the help of suitable transform of the independent variable, the differential equation
\(x\frac{d^2y}{dx^2}+\frac{2dy}{dx}=6x+\frac{1}{x}\) reduces to the form:

• A. \(\frac{d^2y}{dt^2}+2\frac{dy}{dt}=6e^{2t}+1\)
• B. \(\frac{d^2y}{dt^2}+\frac{dy}{dt}=6e^{2t}+1\)
• C. \(\frac{d^2y}{dt^2}=6^{2t}+logt\)
• D. \(\frac{d^2y}{dt^2}=6e^t+t\)

Answer 1

The Correct Option is B

The correct option is (B): \(\frac{d^2y}{dt^2}+\frac{dy}{dt}=6e^{2t}+1\)