Question:

Why does the +3 and +4 oxidation state of Cerium (Ce) remain stable?

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The stability of oxidation states in lanthanides depends on electronic configuration and lattice energy.
Updated On: Mar 5, 2025
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Solution and Explanation

Cerium (\( Ce \)) has an atomic number of 58, with the electronic configuration: \[ [Xe] 4f^1 5d^1 6s^2. \] The \( +3 \) state is stable due to the removal of outer electrons (\( 6s^2, 5d^1 \)), while the \( +4 \) state achieves a stable \( 4f^0 \) configuration.
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