Let the other two numbers be y and z.
As per the condition
73yz - 37yz = 720
Or 36yz=720
Or yz=20
Minimum possible sum of the squares of the other two numbers would occur when y = z i.e.
y = z = √20
Hence the required sum = 40.
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: