Which reagent will be used for the following reaction?
CH3CH2CH2CH3 →
Step 1: Identifying the Reaction Type
- The given reaction involves a simple alkane (butane, \( C_4H_{10} \)).
- Alkanes undergo free radical substitution reactions in the presence of halogens and UV light.
Step 2: Reaction Mechanism
The reaction follows a free radical chain mechanism consisting of three steps: 1. Initiation Step: Formation of chlorine radicals under UV light \[ Cl_2 \xrightarrow{UV} 2Cl\cdot \] 2. Propagation Step: Substitution of a hydrogen atom in butane \[ C_4H_{10} + Cl\cdot \rightarrow C_4H_9\cdot + HCl \] \[ C_4H_9\cdot + Cl_2 \rightarrow C_4H_9Cl + Cl\cdot \] 3. Termination Step: Combination of free radicals to stop the chain reaction \[ Cl\cdot + Cl\cdot \rightarrow Cl_2 \]
Step 3: Conclusion
- The reagent required for this reaction is chlorine (\( Cl_2 \)) and ultraviolet (UV) light.
- The UV light helps break the Cl-Cl bond, generating chlorine radicals that drive the reaction.
The structure of the major product formed in the following reaction is:
The steam volatile compounds among the following are:
The structure of the major product formed in the following reaction is:
If the value of \( \cos \alpha \) is \( \frac{\sqrt{3}}{2} \), then \( A + A = I \), where \[ A = \begin{bmatrix} \sin\alpha & -\cos\alpha \\ \cos\alpha & \sin\alpha \end{bmatrix}. \]