In both molecules i.e., \(NH_3\) and \(NF_3\), the central atom \((N)\) has a lone pair electron and there are three bond pairs. Hence, both molecules have a pyramidal shape. Since fluorine is more electronegative than hydrogen, it is expected that the net dipole moment of \(NF_3\) is greater than \(NH_3\). However, the net dipole moment of \(NH_3\) \((1.46 \;D)\) is greater than that of \(NF_3\) \((0.24 \;D)\).
This can be explained on the basis of the directions of the dipole moments of each individual bond in NF3 and NH3. These directions can be shown as:
Thus, the resultant moment of the \(N-H\) bonds add up to the bond moment of the lone pair (the two being in the same direction), whereas that of the three \(N - F\) bonds partly cancels the moment of the lone pair.
Hence, the net dipole moment of \(NF_3\) is less than that of \(NH_3\).
The bond angles \( b_1, b_2, b_3 \) in the above structure are respectively in \( ^\circ \):
The correct order of bond enthalpy \(\left( kJ mol ^{-1}\right)\) is :
What inference do you draw about the behaviour of Ag+ and Cu2+ from these reactions?
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.