



To determine which compound shows geometrical isomerism, we need to understand what geometrical isomerism is. Geometrical isomerism, also known as cis-trans isomerism, is a type of stereoisomerism that occurs in alkenes and other compounds wherein geometry or the spatial arrangement of atoms or groups around a double bond can result in different isomers.
For a compound to show geometrical isomerism, the following conditions must be met:
Let's analyze the given options:




Option 3, represented in Fig 3, satisfies the conditions for geometrical isomerism, where different groups are attached to the carbons of a double bond, allowing cis-trans isomers.
Conclusion: The correct answer is option 3.
The compound in option (3) shows geometrical isomerism due to the unsymmetrical arrangement around the double bond.
The Correct Answer is: 
For the thermal decomposition of reactant AB(g), the following plot is constructed. 
The half life of the reaction is 'x' min.
x =_______} min. (Nearest integer)}
\(X\) is the number of geometrical isomers exhibited by \([\mathrm{Pt(NH_3)(H_2O)BrCl}]\).
\(Y\) is the number of optically inactive isomer(s) exhibited by \([\mathrm{CrCl_2(ox)_2}]^{3-}\).
\(Z\) is the number of geometrical isomers exhibited by \([\mathrm{Co(NH_3)_3(NO_2)_3}]\). Find the value of \(X + Y + Z\). }
The incorrect statements regarding geometrical isomerism are:
(A) Propene shows geometrical isomerism.
(B) Trans isomer has identical atoms/groups on the opposite sides of the double bond.
(C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene.
(D) 2-methylbut-2-ene shows two geometrical isomers.
(E) Trans-isomer has lower melting point than cis isomer.


Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II):
are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below: