Question:

Which one of the following statements is true?

Show Hint

Disjoint cycles’ orders combine via the LCM rule, so a 3-cycle and a 2-cycle together generate order 6.
Updated On: Dec 6, 2025
  • Exactly half of the elements in any even-order subgroup of \(S_5\) must be even permutations.
  • Any abelian subgroup of \(S_5\) is trivial.
  • There exists a cyclic subgroup of \(S_5\) of order 6.
  • There exists a normal subgroup of \(S_5\) of index 7.
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Analyze cyclic subgroups.
A 6-cycle would have order 6, but \(S_5\) has only 5 symbols. However, a permutation composed of a 3-cycle and a disjoint 2-cycle, such as \((1\,2\,3)(4\,5)\), has order \(\mathrm{lcm}(3,2) = 6\). Hence, it generates a cyclic subgroup of order 6.
Step 2: Check other options.
(A) Not always true. (B) False, since abelian subgroups like \(\langle (1\,2) \rangle\) exist. (D) Index 7 would imply order \(|S_5|/7 = 120/7\), not an integer, impossible.
Step 3: Conclusion.
Hence, only (C) is correct.
Was this answer helpful?
0
0

Questions Asked in IIT JAM MA exam

View More Questions