Question:
Which one of the following reactions will not form acetaldehyde ?
Which one of the following reactions will not form acetaldehyde ?
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To stop at the aldehyde stage using Chromium reagents, use {PCC} (Pyridinium Chlorochromate) in $CH_2Cl_2$. Aqueous $Cr(VI)$ reagents always go to the carboxylic acid.
Updated On: Feb 2, 2026
- CH$_2$=CH$_2$ + O$_2$ $\xrightarrow{Pd(II)/Cu(II)}$ H$_2$O
- CH$_3$CH$_2$OH $\xrightarrow{CrO_3 - H_2SO_4}$
- CH$_3$CN $\xrightarrow{(i) DIBAL-H (ii) H_2O}$
- CH$_3$CH$_2$OH $\xrightarrow{Cu, 573 K}$
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The Correct Option is B
Solution and Explanation
Step 1: (A) is the Wacker Process, which converts ethene to acetaldehyde.
Step 2: (B) Uses Jones Reagent ($CrO_3/H_2SO_4$), which is a strong oxidizing agent. It will oxidize ethanol past the aldehyde stage directly to Acetic Acid.
Step 3: (C) DIBAL-H reduces nitriles selectively to aldehydes.
Step 4: (D) Catalytic dehydrogenation of primary alcohols over hot Copper gives aldehydes.
Step 2: (B) Uses Jones Reagent ($CrO_3/H_2SO_4$), which is a strong oxidizing agent. It will oxidize ethanol past the aldehyde stage directly to Acetic Acid.
Step 3: (C) DIBAL-H reduces nitriles selectively to aldehydes.
Step 4: (D) Catalytic dehydrogenation of primary alcohols over hot Copper gives aldehydes.
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