Question:

Which one of the following is not correct with respect to properties of amines?

Updated On: Apr 4, 2025
  • $pK_b$ of aniline is more than that of methylamine.
  • Ethylamine is soluble in water whereas aniline is not
  • Aniline does not undergo Friedel-Crafts reaction.

  • Ethylamine reacts with nitrous acid to give ethanol.
  • Ethanamide on reaction with $Br_2$ and NaOH gives ethylamine.

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Solution and Explanation

Let’s analyze each statement about amines

\( pK_b \) of aniline is more than that of methylamine: True. Aniline is a weaker base than methylamine due to resonance delocalization of the lone pair on nitrogen into the benzene ring. Hence, it has a higher \( pK_b \).

Ethylamine is soluble in water whereas aniline is not: True. Ethylamine, being a small and polar molecule, forms hydrogen bonds with water and is soluble. Aniline is less polar and has limited solubility because of the bulky aromatic ring.

Ethanamide on reaction with \( Br_2 \) and NaOH gives ethylamine: False. This is incorrect. The reaction of ethanamide with bromine and sodium hydroxide (Hofmann bromamide reaction) gives methylamine, not ethylamine.

Ethylamine reacts with nitrous acid to give ethanol: True. Primary aliphatic amines like ethylamine react with nitrous acid to form ethanol through diazonium salt decomposition.

Aniline does not undergo Friedel–Crafts reaction: True. The lone pair on nitrogen in aniline interacts with the Lewis acid catalyst (such as AlCl₃), which deactivates the aromatic ring and prevents the Friedel–Crafts reaction.

Correct Answer: (C)

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