Which one is the anhydride of \(HClO_4\)?
Which one is the anhydride of \(HClO_4\)?
- $Cl_2O$
- $ClO_2$
- $Cl_2O_6$
- $Cl_2O_7$
The Correct Option is D
Solution and Explanation
\({2HClO_4 \to H_2O + CI_2O_7}\)
\(CI_2O_7\) is an anhydride of HClO4. An anhydride is the chemical compound that is formed from another compound by the removal of water molecules. Anhydride means without water.
So, the correct answer is (D): Cl2O7
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family