Step 1: Analyze Fringe Width
Single slit diffraction fringes are unequal in width. Central bright fringe is widest.
Step 2: Analyze Fringe Width (Statement (i) vs (ii))
(i) Fringes are of unequal width - Correct
(ii) Fringes are of equal width - Incorrect
Step 3: Analyze Energy Conservation
Diffraction is redistribution of energy. Energy is conserved.
Step 4: Analyze Energy Conservation (Statement (iii))
(iii) Light energy is conserved - Correct
Step 5: Analyze Bright Fringe Intensities
Intensities of bright fringes are not equal. Central fringe is most intense; intensity decreases for outer fringes.
Step 6: Analyze Bright Fringe Intensities (Statement (iv))
(iv) Intensities of all bright fringes are equal - Incorrect
Step 7: Identify Correct Statements
Correct statements are (i) and (iii).
Step 8: Match to Option
Option (A) is (i) and (iii).
Final Answer: The final answer is $(i) \text{ and } (iii)$
(i) Fringes are of unequal width: This statement is incorrect. In single slit diffraction, the fringes are not of unequal width. The central maximum is wider than the secondary maxima, but the overall structure of the fringes involves equal angular width for all diffraction fringes.
(ii) Fringes are of equal width: This statement is correct. The angular width of all the diffraction fringes (except the central one) is the same, though the intensity of the fringes changes.
(iii) Light energy is conserved: This statement is correct. The total energy in the diffraction pattern is the same as the energy incident on the slit. The energy is redistributed, but the total energy is conserved.
(iv) Intensities of all bright fringes are equal: This statement is incorrect. In a single slit diffraction pattern, the intensity of the bright fringes decreases as we move away from the central maximum.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is