Which of the given values of x and y make the following pair of matrices equal \(\begin{bmatrix}3x+y&5\\y+1&2-3x\end{bmatrix}=\begin{bmatrix}0&y-2\\8&4\end{bmatrix}\)
\(x=\frac{-1}{3},y=7\)
Not possible to find
\(y=7,x=\frac{-2}{3}\)
\(x=\frac{-1}{3},y=\frac{-2}{3}\)
It is given that \(\begin{bmatrix}3x+y&5\\y+1&2-3x\end{bmatrix}=\begin{bmatrix}0&y-2\\8&4\end{bmatrix}\)
Equating the corresponding elements, we get:
3x+7=0 \(\Rightarrow\)x=\(-\frac{7}{3}\)
5=y-2 \(\Rightarrow\) y=7
y+1=8 \(\Rightarrow\) y=7
2-3x=4 \(\Rightarrow\) x=\(-\frac{2}{3}\)
We find that on comparing the corresponding elements of the two matrices, we get two different values of x, which is not possible.
Hence, it is not possible to find the values of x and y for which the given matrices are equal.
Let \[ f(x)=\int \frac{7x^{10}+9x^8}{(1+x^2+2x^9)^2}\,dx \] and $f(1)=\frac14$. Given that 

A ladder of fixed length \( h \) is to be placed along the wall such that it is free to move along the height of the wall.
Based upon the above information, answer the following questions:
(iii) (b) If the foot of the ladder, whose length is 5 m, is being pulled towards the wall such that the rate of decrease of distance \( y \) is \( 2 \, \text{m/s} \), then at what rate is the height on the wall \( x \) increasing when the foot of the ladder is 3 m away from the wall?
A matrix is a rectangular array of numbers, variables, symbols, or expressions that are defined for the operations like subtraction, addition, and multiplications. The size of a matrix is determined by the number of rows and columns in the matrix.
