Question:

Which of the following statements is true for the carbonyl group?

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In the carbonyl group, the carbon is sp\(^2\) hybridized, and it forms three sigma bonds, one with oxygen and two with substituent groups.
Updated On: Jan 27, 2026
  • Carbon atom is sp\(^3\) hybridised
  • Carbon atom forms three sigma bonds
  • C-C-O bond angle is 90°
  • The carbonyl bond is weaker as compared to the double bond in alkene
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the carbonyl group.
In the carbonyl group (C=O), the carbon is sp\(^2\) hybridized and forms two sigma bonds: one with oxygen and the other with a substituent group. The third sigma bond is formed by the single bond to the other substituent group, such as a hydrogen or alkyl group.

Step 2: Analyzing the options.
(A) Carbon atom is sp\(^3\) hybridised: This is incorrect because the carbon in the carbonyl group is sp\(^2\) hybridized.
(B) Carbon atom forms three sigma bonds: This is correct. The carbon in the carbonyl group forms three sigma bonds.
(C) C-C-O bond angle is 90°: This is incorrect because the bond angle around the carbonyl carbon is about 120°, not 90°.
(D) The carbonyl bond is weaker as compared to the double bond in alkene: This is incorrect. The carbonyl bond is stronger than the double bond in an alkene due to the presence of both sigma and pi bonds.

Step 3: Conclusion.
The correct answer is (B) Carbon atom forms three sigma bonds.
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