Correct Answer:
Option 1: Equilibrium constant may increase or decrease, but rate constant always increases with temperature.
Explanation:
Rate Constant (k):
The rate constant (k) is related to temperature by the Arrhenius equation: k = A * e(-Ea/RT).
As temperature (T) increases, the rate constant (k) always increases.
Equilibrium Constant (K):
The equilibrium constant (K) is related to the rate constants of the forward and reverse reactions: K = kf / kr.
The temperature dependence of K is given by the van 't Hoff equation: d(ln K)/dT = ΔH°/RT2.
Therefore, the equilibrium constant can either increase or decrease, depending on the reaction.
A(g) $ \rightarrow $ B(g) + C(g) is a first order reaction.
The reaction was started with reactant A only. Which of the following expression is correct for rate constant k ?
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is
For $\mathrm{A}_{2}+\mathrm{B}_{2} \rightleftharpoons 2 \mathrm{AB}$ $\mathrm{E}_{\mathrm{a}}$ for forward and backward reaction are 180 and $200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively. If catalyst lowers $\mathrm{E}_{\mathrm{a}}$ for both reaction by $100 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Which of the following statement is correct?