Question:

Which of the following statements is incorrect about sucrose?

Show Hint

Reducing sugars have a hemiacetal or hemiketal end group, while non-reducing sugars do not. If there is a free aldehyde or ketone group, it’ll react with Benedicts and Tollens reagents and reduce them. The glucose and fructose residues of sucrose are linked through their anomeric carbons, resulting in a non-reducing sugar.
Updated On: Jan 2, 2025
  • Ordinary table sugar is called sucrose
  • Sucrose is a disaccharide
  • \(Sucrose\ has\ a\ molecular\ formula\ of\ C_{12}H_{22}O_{11}\)
  • Sucrose gives a positive test with Benedict’s and Tollens’ solutions
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Sucrose is a non-reducing sugar because it does not have a free aldehyde or ketone group. In sucrose, the glucose and fructose units are linked by their anomeric carbons, preventing the molecule from reacting with Benedict’s or Tollens’ solutions. Other points:
• Sucrose is commonly referred to as table sugar.
• It is a disaccharide with the formula \(C_{12}H_{22}O_{11}\).
• Non-reducing sugars do not participate in redox reactions typical of reducing sugars.

Was this answer helpful?
0
0