Which of the following statements concerning methylamine is correct?
Show Hint
- Methylamine is stronger base than NH\(_3\)
- Methylamine is less basic than NH\(_3\)
- Methylamine is slightly acidic
- Methylamine forms salts with alkali
The Correct Option is A
Solution and Explanation
Methylamine (CH\(_3\)NH\(_2\)) is a stronger base than ammonia (NH\(_3\)) because the methyl group (CH\(_3\)) is an electron-donating group, which increases the electron density on nitrogen and makes it more readily available to accept protons.
Step 2: Explanation of Other Options
Option (b) is incorrect because methylamine is a stronger base than ammonia.
Option (c) is incorrect because methylamine is not acidic, it is basic.
Option (d) is incorrect because both methylamine and ammonia can form salts with acids, but this does not affect their basicity directly.
Step 3: Conclusion
Thus, methylamine is a stronger base than NH\(_3\).
Top Questions on Amines
Amines have a lone pair of electrons on the nitrogen atom, due to which they behave as Lewis bases. Greater the value of \( K_b \) or smaller the value of \( pK_b \), stronger is the base. Amines are more basic than alcohols, ethers, esters, etc. The basic character of aliphatic amines should increase with the increase of alkyl substitution. However, it does not occur in a regular manner, as a secondary aliphatic amine is unexpectedly more basic than a tertiary amine in aqueous solutions. Aromatic amines are weaker bases than ammonia and aliphatic amines. Electron-releasing groups such as \( -CH_3 \), \( -NH_2 \), etc., increase the basicity, while electron-withdrawing substituents such as \( -NO_2 \), \( -CN \), halogens, etc., decrease the basicity of amines. The effect of these substituents is more pronounced at the para-position than at the meta-position.
Arrange the following in increasing order of their basic character. Give reason:
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Amides are less basic than amines. - Give plausible explanation for each of the following:
Aromatic primary amines cannot be prepared by Gabriel Phthalimide synthesis. - Arrange the following compounds in increasing order of their boiling point:
\[ \text{(CH}_3\text{)}_2\text{NH, CH}_3\text{CH}_2\text{NH}_2, \text{CH}_3\text{CH}_2\text{OH} \] - The best reagent for converting propanamide into propanamine is:
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