To solve the problem, we need to arrange the given compounds in increasing order of their boiling points.
1. Understanding the Boiling Points:
Boiling points of compounds are influenced by intermolecular forces such as hydrogen bonding, dipole-dipole interactions, and London dispersion forces. Stronger intermolecular forces usually result in higher boiling points.
2. Analyzing the Compounds:
The given compounds are:
- (CH₃)₂NH (Dimethylamine)
- CH₃CH₂NH₂ (Ethylamine)
- CH₃CH₂OH (Ethanol)
3. Boiling Points of Compounds:
- (CH₃)₂NH (Dimethylamine): This compound is a simple amine. It exhibits hydrogen bonding, but it is weaker compared to alcohols. - CH₃CH₂NH₂ (Ethylamine): This is another amine, but it has a slightly higher boiling point than dimethylamine due to its larger molecular size and stronger dipole-dipole interactions. - CH₃CH₂OH (Ethanol): This compound has a hydroxyl group (-OH), which allows for strong hydrogen bonding, leading to a higher boiling point compared to the amines.
4. Order of Boiling Points:
We can now arrange the compounds in increasing order of their boiling points based on the strength of the intermolecular forces:
Increasing Order of Boiling Points:
(CH₃)₂NH < CH₃CH₂NH₂ < CH₃CH₂OH
Final Answer:
The compounds in increasing order of their boiling points are:
(CH₃)₂NH < CH₃CH₂NH₂ < CH₃CH₂OH.
For the reaction sequence given below, the correct statement(s) is(are):
Amines have a lone pair of electrons on the nitrogen atom, due to which they behave as Lewis bases. Greater the value of \( K_b \) or smaller the value of \( pK_b \), stronger is the base. Amines are more basic than alcohols, ethers, esters, etc. The basic character of aliphatic amines should increase with the increase of alkyl substitution. However, it does not occur in a regular manner, as a secondary aliphatic amine is unexpectedly more basic than a tertiary amine in aqueous solutions. Aromatic amines are weaker bases than ammonia and aliphatic amines. Electron-releasing groups such as \( -CH_3 \), \( -NH_2 \), etc., increase the basicity, while electron-withdrawing substituents such as \( -NO_2 \), \( -CN \), halogens, etc., decrease the basicity of amines. The effect of these substituents is more pronounced at the para-position than at the meta-position.
Arrange the following in increasing order of their basic character. Give reason:
(A) Explain the following reactions and write chemical equations involved:
(a) Wolff-Kishner reduction
(b) Etard reaction
(c) Cannizzaro reaction