Which of the following statement pattern is a contradiction?
S4 ≡ (∼p ˄ q) ˅ (∼q)
S2 ≡ (p →q) ˅ (p ˄ ∼q)
S1 ≡ (∼p ˅ ∼q) ˅ (p ˅ ∼q)
S3 ≡ (∼p ˄ q) ˄ (∼q)
To determine if a statement pattern is a contradiction, we are looking for a pattern that evaluates to false (contradiction) regardless of the truth values of the variables involved.
By examining the statement patterns, we can see that the contradictory pattern is:
(D) S3 ≡ (∼p ˄ q) ˄ (∼q)
In this pattern, the conjunction (∧) of (∼q) and (∼q) is contradictory because it states that q is both true and false at the same time. This results in a contradiction, making statement pattern (D) contradictory.
Therefore, the statement pattern (D) is the contradiction.
In the (4 times 4) array shown below, each cell of the first three rows has either a cross (X) or a number. The number in a cell represents the count of the immediate neighboring cells (left, right, top, bottom, diagonals) NOT having a cross (X). Given that the last row has no crosses (X), the sum of the four numbers to be filled in the last row is:
Let \( \{(a, b) : a, b \in {R, a<b \} }\) be a basis for a topology \( \tau \) on \( {R} \). Which of the following is/are correct?