Step 1: Lindemann mechanism overview.
The Lindemann mechanism suggests that the decomposition of a molecule follows first-order kinetics at low pressure, where the rate of decomposition is dependent on the concentration of the reactant. At high pressures, the reaction can follow second-order kinetics due to the increased number of collisions.
Step 2: Analysis of options.
- (1) It follows second order kinetics at high pressure: This is true for high-pressure conditions, but not the best fit for the unimolecular decomposition at low pressure.
- (2) It follows second order kinetics at low pressure: This is not correct; Lindemann mechanism typically follows first-order kinetics at low pressure.
- (3) The kinetics of the reaction does not depend on the gaseous pressure: This is not accurate; the kinetics depend on pressure.
- (4) It follows first order kinetics at low pressure: This is correct according to the Lindemann mechanism.
Step 3: Conclusion.
The correct answer is (4), as the reaction follows first-order kinetics at low pressure.
| Time (Hours) | [A] (M) |
|---|---|
| 0 | 0.40 |
| 1 | 0.20 |
| 2 | 0.10 |
| 3 | 0.05 |
Reactant ‘A’ underwent a decomposition reaction. The concentration of ‘A’ was measured periodically and recorded in the table given below:
Based on the above data, predict the order of the reaction and write the expression for the rate law.
For the reaction \( A + B \to C \), the rate law is found to be \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and \( B \) is halved, by what factor does the rate change?

