Step 1: Lindemann mechanism overview.
The Lindemann mechanism suggests that the decomposition of a molecule follows first-order kinetics at low pressure, where the rate of decomposition is dependent on the concentration of the reactant. At high pressures, the reaction can follow second-order kinetics due to the increased number of collisions.
Step 2: Analysis of options.
- (1) It follows second order kinetics at high pressure: This is true for high-pressure conditions, but not the best fit for the unimolecular decomposition at low pressure.
- (2) It follows second order kinetics at low pressure: This is not correct; Lindemann mechanism typically follows first-order kinetics at low pressure.
- (3) The kinetics of the reaction does not depend on the gaseous pressure: This is not accurate; the kinetics depend on pressure.
- (4) It follows first order kinetics at low pressure: This is correct according to the Lindemann mechanism.
Step 3: Conclusion.
The correct answer is (4), as the reaction follows first-order kinetics at low pressure.
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is
For $\mathrm{A}_{2}+\mathrm{B}_{2} \rightleftharpoons 2 \mathrm{AB}$ $\mathrm{E}_{\mathrm{a}}$ for forward and backward reaction are 180 and $200 \mathrm{~kJ} \mathrm{~mol}^{-1}$ respectively. If catalyst lowers $\mathrm{E}_{\mathrm{a}}$ for both reaction by $100 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Which of the following statement is correct?