Which of the following reactions will yield benzaldehyde as a product?
Choose the correct answer from the following options:
Step 1: Analyzing Reaction (A).
The reaction starts with benzoic acid (C₆H₅COOH).
- SOCl₂, Quinoline: SOCl₂ converts the carboxylic acid to the corresponding acyl chloride (C₆H₅COCl).
- H₂/Pd/BaSO₄: Hydrogenation of the acyl chloride reduces it to the corresponding aldehyde, benzaldehyde (C₆H₅CHO). Thus, Reaction (A) yields benzaldehyde.
Step 2: Analyzing Reaction (B).
The reaction starts with benzyl alcohol (C₆H₅CH₂OH).
- CrO₃/H₂SO₄: This reagent is used to oxidize alcohols to aldehydes.
- Benzyl alcohol is oxidized to benzaldehyde (C₆H₅CHO).
Step 3: Analyzing Reaction (C).
The reaction starts with anisole (C₆H₅OCH₃).
- NaBH₄: This is a mild reducing agent that typically reduces carbonyl compounds (like esters or ketones) to alcohols. - PCC: This reagent is used to oxidize alcohols to aldehydes.
- Anisole undergoes reduction to benzyl alcohol (C₆H₅CH₂OH) via NaBH₄, and then PCC oxidizes it to benzaldehyde (C₆H₅CHO).
Step 4: Analyzing Reaction (D).
The reaction starts with toluene (C₆H₅CH₃). - CrO₃: Chromium trioxide oxidizes methyl groups (CH₃) to the corresponding aldehyde, resulting in benzaldehyde. - (CH₃CO)₂O is a reagent typically used in Friedel-Crafts acylation, but in this reaction setup, it does not interfere with the oxidation step. The final product is benzaldehyde. Thus, Reaction (D) gives benzaldehyde.
Conclusion: The reactions that yield benzaldehyde are (A) and (D). Therefore, the correct answer is (C) (A) and (D).
The correct increasing order of stability of the complexes based on \( \Delta \) value is:
List I (Molecule) | List II (Number and types of bond/s between two carbon atoms) | ||
A. | ethane | I. | one σ-bond and two π-bonds |
B. | ethene | II. | two π-bonds |
C. | carbon molecule, C2 | III. | one σ-bonds |
D. | ethyne | IV. | one σ-bond and one π-bond |