Which of the following reactions will NOT give primary amine as the product
Which of the following reactions will NOT give primary amine as the product
The Correct Option is B
Approach Solution - 1
The question asks which reaction will NOT produce a primary amine. To determine this, we must analyze each reaction path to understand the type of product formed. Primary amines have the general formula R-NH2.
Let's evaluate each option:
- Option 1: This reaction involves the reduction of a nitrile (RCN) using hydrogen in the presence of a catalyst, typically producing a primary amine (RNH2).
- Option 2: This process involves a reaction of an alkyl halide with ammonia (NH3). Typically, this method results in a mixture of primary, secondary, and tertiary amines due to multiple alkylation. Therefore, it does not exclusively produce a primary amine.
- Option 3: The reduction of an amide (RCONH2) using a reducing agent like LiAlH4 results in a primary amine (RNH2).
- Option 4: The reduction of an azide (RN3) usually results in a primary amine (RNH2).
Based on the analysis, Option 2 is the reaction which will NOT exclusively produce a primary amine due to the possibility of over-alkylation.
Approach Solution -2
The correct option is (B): 
Top Questions on Amines
- Assertion (A): Boiling point of (C6H5)2NH is lower than that of n-C4H9NH2. Reason (R): Hydrogen bonding is much more extensive in (C6H5)2NH as compared to n- C4H9NH2.
- Arrange the following compounds as asked:
(a) In decreasing order of pKb values
C2H5NH2, (C2H5)2NH, C6H5NHCH3, C6H5NH2
(b) In increasing order of boiling point
C2H5OH, C2H5NH2, (CH3)2NH
(c) In increasing order of solubility in water
C6H5NH2, (C2H5)2NH, C2H5NH2 - Arrange the following compounds as asked:
(a) In decreasing order of pKb, values: C$_6$H$_5$NH$_2$, (C$_2$H$_5$)$_2$NH, C$_6$H$_5$NHCH$_2$CH$_3$, C$_6$H$_5$NH$_3$
(b) Increasing order of boiling point: C$_6$H$_5$OH, C$_2$H$_5$NH$_2$, (C$_2$H$_5$)$_2$NH, C$_6$H$_5$NH$_2$
(c) Increasing order of solubility in water: C$_6$H$_5$NH$_2$, (C$_2$H$_5$)$_2$NH, C$_6$H$_5$NHCH$_2$CH$_3$ - Assertion (A): Acetanilide is less basic than aniline.
Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen. - Hoffmann Bromamide degradation reaction is given by:
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Concepts Used:
Amines
Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.
Amine - Types
Primary Amines:
It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.
Secondary Amines:
Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.
Tertiary Amines:
Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.