Deuterium oxide (\( {D}_2{O} \)) has a higher molecular mass compared to normal water (\( {H}_2{O} \)), which leads to slightly different physical properties. While the properties like melting point, enthalpy of vaporization, and viscosity are relatively similar, the dielectric constant of \( {D}_2{O} \) is less than that of \( {H}_2{O} \). This is because the increased mass of deuterium affects the polarizability and the ability to stabilize charges, leading to a lower dielectric constant.
Final Answer: Dielectric constant.
If the roots of $\sqrt{\frac{1 - y}{y}} + \sqrt{\frac{y}{1 - y}} = \frac{5}{2}$ are $\alpha$ and $\beta$ ($\beta > \alpha$) and the equation $(\alpha + \beta)x^4 - 25\alpha \beta x^2 + (\gamma + \beta - \alpha) = 0$ has real roots, then a possible value of $y$ is: