Question

KMnO₄ decomposes on heating at 513 K to form O₂ along with

• A. \(MnO_4^- , MnO_2\)
• B. \(K_2MnO_4 , MnO_2\)
• C. \(KMnO_4 , MnO_2\)
• D. \(MnO_2, H_2O\)

Answer 1

The Correct Option is B

To solve the problem of determining what substances are formed when potassium permanganate (\(KMnO_4\)) decomposes upon heating at 513 K, we need to understand the chemical decomposition reaction involved. 

When \(KMnO_4\) is heated, it decomposes into potassium manganate (\(K_2MnO_4\)), manganese dioxide (\(MnO_2\)), and oxygen gas (\(O_2\)). The balanced chemical reaction for this decomposition is given by:

\(2KMnO_4 \rightarrow K_2MnO_4 + MnO_2 + O_2\)

Let's analyze the options:

• \(MnO_4^- , MnO_2\): This option mentions the manganate ion but lacks potassium.
• \(K_2MnO_4 , MnO_2\): This matches the known decomposition reaction products.
• \(KMnO_4 , MnO_2\): This does not involve any formation or release of oxygen, and \(KMnO_4\) is the reactant itself.
• \(MnO_2, H_2O\): Water (\(H_2O\)) is not a product of this decomposition reaction.

The only option that correctly represents the components formed by the decomposition of \(KMnO_4\) is:

• \(K_2MnO_4 , MnO_2\).

Thus, the correct answer is:

• \(K_2MnO_4 , MnO_2\)

Answer 2

\(KMnO_4\) decomposes upon heating at 513 K and forms \(K_2MnO_4\) and \(MnO_2\).

\(2KMnO4 \xrightarrow{\Delta} K_2MnO_4 + O2 + MnO2\)

So, the Correct option is (B): \(K_2MnO_4\), \(MnO_2\)