KMnO4 decomposes on heating at 513 K to form O2 along with
- \(MnO_4^- , MnO_2\)
- \(K_2MnO_4 , MnO_2\)
- \(KMnO_4 , MnO_2\)
- \(MnO_2, H_2O\)
The Correct Option is B
Approach Solution - 1
To solve the problem of determining what substances are formed when potassium permanganate (\(KMnO_4\)) decomposes upon heating at 513 K, we need to understand the chemical decomposition reaction involved.
When \(KMnO_4\) is heated, it decomposes into potassium manganate (\(K_2MnO_4\)), manganese dioxide (\(MnO_2\)), and oxygen gas (\(O_2\)). The balanced chemical reaction for this decomposition is given by:
| \(2KMnO_4 \rightarrow K_2MnO_4 + MnO_2 + O_2\) |
Let's analyze the options:
- \(MnO_4^- , MnO_2\): This option mentions the manganate ion but lacks potassium.
- \(K_2MnO_4 , MnO_2\): This matches the known decomposition reaction products.
- \(KMnO_4 , MnO_2\): This does not involve any formation or release of oxygen, and \(KMnO_4\) is the reactant itself.
- \(MnO_2, H_2O\): Water (\(H_2O\)) is not a product of this decomposition reaction.
The only option that correctly represents the components formed by the decomposition of \(KMnO_4\) is:
- \(K_2MnO_4 , MnO_2\).
Thus, the correct answer is:
- \(K_2MnO_4 , MnO_2\)
Approach Solution -2
\(KMnO_4\) decomposes upon heating at 513 K and forms \(K_2MnO_4\) and \(MnO_2\).
\(2KMnO4 \xrightarrow{\Delta} K_2MnO_4 + O2 + MnO2\)
So, the Correct option is (B): \(K_2MnO_4\), \(MnO_2\)
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