Question

Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is :
\includegraphics[width=0.5\linewidth]{Screenshot 2026-02-04 151835.png}

• A. 1
• B. 2
• C. 3
• D. 4

Hint:

The Hofmann Bromamide reaction always removes the carbonyl carbon from the amide. If your final amine has $n$ carbons, your starting amide (and acid) must have $n+1$ carbons.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept:
This problem involves identifying a starting material through a series of nitrogen-based organic reactions, including amide formation, the Hofmann Bromamide degradation, and the Carbylamine reaction.
Step 2: Detailed Explanation:
Working backward from the final product, Methyl Isocyanide ($CH_3-NC$):
1. The Carbylamine reaction (treatment with $CHCl_3$ and $KOH$) produces an isocyanide from a primary amine. Therefore, the precursor to $CH_3-NC$ must be Methylamine ($CH_3-NH_2$).
2. The Hofmann Bromamide degradation (treatment with $Br_2$ and $KOH$) produces a primary amine with one fewer carbon atom from an amide. To get $CH_3-NH_2$, the precursor amide 'Q' must be Ethanamide ($CH_3CONH_2$).
3. 'Q' ($CH_3CONH_2$) is formed by reacting 'P' with $NH_3$ and heating. This is a standard synthesis of amides from carboxylic acids. Therefore, 'P' must be Ethanoic acid (Acetic acid), $CH_3COOH$.
Step 3: Final Answer:
Compound 'P' is CH₃-C(O)-OH.