To solve the problem, we need to determine which pair of devices measures the same physical quantity.
1. Understanding the Devices:
- Ammeter: Measures electric current flowing through a circuit.
- Galvanometer: A sensitive instrument used to detect and measure small electric currents.
- Voltmeter: Measures potential difference (voltage) between two points.
- Ohmmeter: Measures electrical resistance.
2. Comparing the Pairs:
- Option (1): Ammeter and Galvanometer — both measure current (galvanometer for small currents, ammeter for larger currents). ✅
- Option (2): Ammeter (current), Voltmeter (voltage) — different quantities ❌
- Option (3): Galvanometer (current), Voltmeter (voltage) — different quantities ❌
- Option (4): Ammeter (current), Ohmmeter (resistance) — different quantities ❌
Final Answer:
The correct pair that measures the same physical quantity is \({\text{Ammeter, Galvanometer}} \).
In the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage \( E \) for unit change in the resistance \( R \), in V/Ω, is __________ (round off to two decimal places).
An ideal low pass filter has frequency response given by \[ H(j\omega) = \begin{cases} 1, & |\omega| \leq 200\pi \\ 0, & \text{otherwise} \end{cases} \] Let \( h(t) \) be its time domain representation. Then h(0) = _________ (round off to the nearest integer).