Step 1: Define glycosidic linkage. A glycosidic linkage is a type of covalent bond that joins a carbohydrate molecule to another group, which can be another carbohydrate. It is formed by a dehydration reaction between two monosaccharides.
Step 2: Analyze each molecule. Sucrose (table sugar) is a disaccharide consisting of glucose and fructose linked via a glycosidic bond.
Glucose is a simple sugar or monosaccharide, lacking glycosidic linkages as it does not bond with another sugar in its basic form.
Maltose is a disaccharide composed of two glucose units linked by a glycosidic bond.
Cellulose is a polysaccharide made up of multiple glucose units linked by glycosidic bonds, forming the structural component of plant cell walls. Conclusion: Glucose, being a monosaccharide, does not have glycosidic linkages, making it the correct answer.
To solve the problem, we need to determine which of the following molecules does not have a glycosidic linkage.
1. Understanding Glycosidic Linkages:
A glycosidic linkage is a covalent bond that forms between two monosaccharide molecules, such as in disaccharides, oligosaccharides, and polysaccharides. This bond is formed when a hydroxyl group (-OH) of one monosaccharide reacts with the anomeric carbon of another monosaccharide, releasing a molecule of water.
2. Analyzing the Options:
Let's examine the molecules:
3. Conclusion:
Glucose is the only molecule listed that does not contain a glycosidic linkage, as it is a monosaccharide.
Final Answer:
The correct answer is (B) Glucose.
An electrochemical cell is fueled by the combustion of butane at 1 bar and 298 K. Its cell potential is $ \frac{X}{F} \times 10^3 $ volts, where $ F $ is the Faraday constant. The value of $ X $ is ____.
Use: Standard Gibbs energies of formation at 298 K are:
$ \Delta_f G^\circ_{CO_2} = -394 \, \text{kJ mol}^{-1}; \quad \Delta_f G^\circ_{water} = -237 \, \text{kJ mol}^{-1}; \quad \Delta_f G^\circ_{butane} = -18 \, \text{kJ mol}^{-1} $
Consider the following electrochemical cell at standard condition. $$ \text{Au(s) | QH}_2\text{ | QH}_X(0.01 M) \, \text{| Ag(1M) | Ag(s) } \, E_{\text{cell}} = +0.4V $$ The couple QH/Q represents quinhydrone electrode, the half cell reaction is given below: $$ \text{QH}_2 \rightarrow \text{Q} + 2e^- + 2H^+ \, E^\circ_{\text{QH}/\text{Q}} = +0.7V $$

In the above diagram, the standard electrode potentials are given in volts (over the arrow). The value of \( E^\circ_{\text{FeO}_4^{2-}/\text{Fe}^{2+}} \) is:
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))