Question:

Which of the following molecule contains 50% p\(_\pi\) character of hybrid orbital in C atom?

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In molecules with sp hybridization like acetylene, the carbon atoms have 50% p\(_\pi\) character, while sp\(^2\) and sp\(^3\) hybridized carbons have different p orbital contributions.
Updated On: Jan 27, 2026
  • Propene
  • Acetylene
  • Methane
  • Ethane
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The Correct Option is B

Solution and Explanation

Step 1: Understanding p\(_\pi\) character.
In acetylene (C\(_2\)H\(_2\)), the carbon atoms undergo sp hybridization, where 50% of the orbital character comes from the p orbitals. This results in a 50% p\(_\pi\) character of the hybrid orbitals.

Step 2: Analyzing the options.
(A) Propene: Propene involves sp\(^2\) hybridization, but it does not exhibit 50% p\(_\pi\) character in its hybridization.
(B) Acetylene: This is the correct answer, as acetylene has a 50% p\(_\pi\) character in its sp hybrid orbitals.
(C) Methane: Methane involves sp\(^3\) hybridization, which has no p\(_\pi\) character.
(D) Ethane: Ethane also involves sp\(^3\) hybridization and does not exhibit p\(_\pi\) character.

Step 3: Conclusion.
The correct answer is (B) Acetylene, as it contains 50% p\(_\pi\) character of hybrid orbitals in carbon atoms.
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