(a) \(ONCl= 8+ 7+ 17= 32e^-\) \(ONO = 8 + 7 + 8 + 1 = 24e^-\) (correct)
(b) Central O-atom is \(sp^2\)-hybridised with 1 lone pair, so bent shape (correct).
(c) In solid state, ozone is violet-black. Ozone does not exist in solid state, thus incorrect.
(d) \(0_3\) has no unpaired electrons, so diamagnetic (correct).
Hence, the correct option is (C): Ozone is violet-black in solid state.
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Match List-I with List-II: List-I