(a) \(ONCl= 8+ 7+ 17= 32e^-\) \(ONO = 8 + 7 + 8 + 1 = 24e^-\) (correct)
(b) Central O-atom is \(sp^2\)-hybridised with 1 lone pair, so bent shape (correct).
(c) In solid state, ozone is violet-black. Ozone does not exist in solid state, thus incorrect.
(d) \(0_3\) has no unpaired electrons, so diamagnetic (correct).
Hence, the correct option is (C): Ozone is violet-black in solid state.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $