A correct set of quantum numbers ($n$, $l$, $m$, $s$) must satisfy the following rules:
Let's check each option:
(3, 0, -1, +1/2): Invalid because $m = -1$ is not allowed for $l = 0$
(4, 3, -2, -1/2): Valid
- $n = 4$
- $l = 3$ (allowed for $n = 4$)
- $m = -2$ (allowed for $l = 3$)
- $s = -1/2$ (allowed)
(3, 1, -2, -1/2): Invalid because $m = -2$ is not allowed for $l = 1$
(4, 2, -3, +1/2): Invalid because $m = -3$ is not allowed for $l = 2$
Answer: (4, 3, -2, -1/2)
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of: