Question:

Which of the following is the correct formulation of the linear programming problem ?

Updated On: Apr 8, 2025
  • Max \(Z=2x_1-x_2\) ;subject to \(x_1+x_2≤10;x_1≤3;x1≥0;x_2≤0 \)

  • Max \(Z=3x_1+2x_2\) ;subject to \( x_1+2x2≥11;3x_1+x_2≥24;x_1≥0;x1,x_2≤0\)

  • Max \(Z=2x_1+5x_2\) ;subject to \(4x_1+9x_2≤8;2x_1+3x_2≤9;x_1≥0;x_1,x_2≤0\)

  •  Min \(Z=4x_1+3x_2\) ;subject to \(x_1+9x_2≥8;2x_1+5x_2≤9;x_1≤0,x_2≥0 \)

  •  Min \(Z=x_1+5x_2\) ;subject to \(2x_1+5x_2≤10;x_1+3x_2≤9;x_1,x_2≥0\)

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The Correct Option is

Approach Solution - 1

The correct formulation must satisfy these requirements:

  1. All variables must have non-negativity constraints (x ≥ 0)
  2. The constraints must form a convex feasible region
  3. The objective function must be linear
  4. Constraints must be properly balanced (≤ for maximization, ≥ for minimization typically)

Evaluating the options:

(A) Invalid because x₂ ≤ 0 violates non-negativity

(B) Invalid because x₁, x₂ ≤ 0 violates non-negativity

(E) Correct because:

  • Minimization problem with proper constraints
  • All variables satisfy x ≥ 0
  • Constraints use ≤ appropriately

(D) Invalid because x₁ ≤ 0 violates non-negativity

(C) Invalid because x₁, x₂ < 0 violates non-negativity

The correct answer is (E) Min Z = x₁ + 5x₂; subject to 2x₁ + 5x₂ ≤ 10; x₁ + 3x₂ ≤ 9; x₁, x₂ ≥ 0.

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Approach Solution -2

A correct formulation of a linear programming problem requires:

  1. A linear objective function: This function should be either maximized or minimized and be a linear combination of the decision variables.
  2. Linear constraints: The constraints should be linear inequalities or equalities involving the decision variables.
  3. Non-negativity restrictions: The decision variables must be non-negative (\(x_1, x_2, \dots \geq 0\)). While some problems allow for unrestricted variables, those can be handled by substitutions; the initial problem must not have variables with both positive and negative bounds simultaneously.

Examining each option we find that:

  • Option 1: Has \(x_2 \leq 0\), meaning that \(x_2\) can take on negative values, and it is not stated that \(x_1\) must be positive. While feasible, it is not a standard LP form.
  • Option 2: Has conflicting restrictions for \(x_1\) and \(x_2\). \(x_1\) must be non-negative, but also less than or equal to zero, which is a contradiction. The constraints are also inequalities in the wrong direction for a maximization problem (they should be less than or equal to).
  • Option 3: Similar to Option 2; conflicting restrictions for \(x_1\) and \(x_2\).
  • Option 4: Has conflicting restrictions for \(x_1\): \(x_1 \leq 0\) and \(x_1 \geq 0\) simultaneously.
  • Option 5: This option satisfies all three conditions. It has a linear objective function to be minimized, linear constraints (all ≤), and non-negativity restrictions on the variables.

Therefore, only Option 5 is a correct formulation of a linear programming problem in standard form.

Final Answer: The final answer is \( \boxed{\text{Min } Z = x_1 + 5x_2; \text{ subject to } 2x_1 + 5x_2 \leq 10; \, x_1 + 3x_2 \leq 9; \, x_1, x_2 \geq 0} \).

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Concepts Used:

Linear Programming Problems

The Linear Programming Problems (LPP) is a problem that is concerned with finding the optimal value of the given linear function. The optimal value can be either maximum value or minimum value. Here, the given linear function is considered an objective function. The objective function can contain several variables, which are subjected to the conditions and it has to satisfy the set of linear inequalities called linear constraints.

Linear Programming Simplex Method

Step 1: Establish a given problem. (i.e.,) write the inequality constraints and objective function.

Step 2: Convert the given inequalities to equations by adding the slack variable to each inequality expression.

Step 3: Create the initial simplex tableau. Write the objective function at the bottom row. Here, each inequality constraint appears in its own row. Now, we can represent the problem in the form of an augmented matrix, which is called the initial simplex tableau.

Step 4: Identify the greatest negative entry in the bottom row, which helps to identify the pivot column. The greatest negative entry in the bottom row defines the largest coefficient in the objective function, which will help us to increase the value of the objective function as fastest as possible.

Step 5: Compute the quotients. To calculate the quotient, we need to divide the entries in the far right column by the entries in the first column, excluding the bottom row. The smallest quotient identifies the row. The row identified in this step and the element identified in the step will be taken as the pivot element.

Step 6: Carry out pivoting to make all other entries in column is zero.

Step 7: If there are no negative entries in the bottom row, end the process. Otherwise, start from step 4.

Step 8: Finally, determine the solution associated with the final simplex tableau.