Step 1: Recall the electron configuration for oxygen
Oxygen (O) has an atomic number of 8, meaning it has 8 electrons.
Step 2: Distribute the electrons in orbitals
The electron configuration follows the Aufbau principle, which fills the lowest energy orbitals first:
- The first shell can hold up to 2 electrons, so the \( 1s \) orbital is filled first: \( 1s^2 \).
- The second shell can hold up to 8 electrons, so the \( 2s \) orbital is filled next: \( 2s^2 \).
- After that, the \( 2p \) orbital starts filling.
Oxygen has 8 electrons in total, so the next 4 electrons will go into the \( 2p \) orbital: \( 2p^4 \).
Therefore, the electron configuration of oxygen is: \[ 1s^2 2s^2 2p^4 \]
Answer:
Therefore, the correct electron configuration for an oxygen atom is \( 1s^2 2s^2 2p^4 \). So, the correct answer is option (1).
Correct statements for an element with atomic number 9 are
A. There can be 5 electrons for which $ m_s = +\frac{1}{2} $ and 4 electrons for which $ m_s = -\frac{1}{2} $
B. There is only one electron in $ p_z $ orbital.
C. The last electron goes to orbital with $ n = 2 $ and $ l = 1 $.
D. The sum of angular nodes of all the atomic orbitals is 1.
Choose the correct answer from the options given below:
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